The equations shown above are included on the exam. Any other equations needed to calculate quantities or pay amounts will need to be known by the

Transcription

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2 The equations shown above are included on the exam. Any other equations needed to calculate quantities or pay amounts will need to be known by the student without the aid of a reference.

3 The equations shown above are included on the exam. Any other equations needed to calculate quantities or pay amounts will need to be known by the student without the aid of a reference.

4 HOMEWORK PROBLEM # 1 Plan Quantity (PQ) Analysis Reference: Module 2 - Method of Measurement & Documentation Determine the Final Pay Quantity for Asphalt Base (Pay Item 285) for Contract No. T3456 and fill in the correct information in the attached Plan Summary Box sheets and/or the plan quantity analysis sheet. This contract contains two (2) projects. The first project (FIN Project No ) contains a Designer Plan Quantity of 5,300 SY from Sta.1+00 to Sta The width is 24 ft. for the entire length. Additional information provided includes: Asphalt Base Unit Price = $15.00 Plan Error = +300 SY Authorized field change = +200 SY The second project (FIN Project No ) contains a Designer Plan Quantity of 2,200 SY from Sta.1+00 to Sta The width is 24 ft. for the entire length. Additional information provided includes: Asphalt Base Unit Price = $15.00 Plan Error = +200 SY Authorized field change = +100 SY

5 HOMEWORK PROBLEM # 1 Plan Quantity (PQ) Analysis Reference: Module 2 - Method of Measurement & Documentation Determine the Final Pay Quantity for Asphalt Base (Pay Item 285) for Contract No. T3456 and fill in the correct information in the attached Plan Summary Box sheets and/or the plan quantity analysis sheet. This contract contains two (2) projects. The first project (FIN Project No ) contains a Designer Plan Quantity of 5,300 SY from Sta.1+00 to Sta The width is 24 ft. for the entire length. Additional information provided includes: Asphalt Base Unit Price = $15.00 Plan Error = +300 SY Authorized field change = +200 SY The second project (FIN Project No ) contains a Designer Plan Quantity of 2,200 SY from Sta.1+00 to Sta The width is 24 ft. for the entire length. Additional information provided includes: Asphalt Base Unit Price = $15.00 Plan Error = +200 SY Authorized field change = +100 SY

6 CALCULATION AREA & NOTES:

7 HOMEWORK PROBLEM # 1 Plan Quantity (PQ) Analysis Reference: Module 2 - Method of Measurement & Documentation

8 HOMEWORK PROBLEM # 1 Plan Quantity (PQ) Analysis Reference: Module 2 - Method of Measurement & Documentation

9 HOMEWORK PROBLEM # 1 Plan Quantity (PQ) Analysis Reference: Module 2 - Method of Measurement & Documentation

10 SOLUTION TO HOMEWORK PROBLEM #1 The key is to remember that the adjustment to a Plan Quantity Item is based on the CONTRACT, not on the individual project within the contract. Total Plan Quantity = 5,300 SY + 2,200 SY = 7,500 SY Total Plan Errors = = SY Analyze the Plan Error quantities to see if they qualify for payment. Per Specifications, either one of these analyses would qualify to change the Plan Quantity. Step 1: Determine if the quantities exceed 5% allowable 500 SY 100 = 6.7% Exceeds the allowable 5% 7,500 SY Step 2: Determine if the quantities exceed $5,000 allowable Solution: Final Pay Quantity for Asphalt Base (Pay Item 285): = Plan Quantity + Plan Error + Field Changes = 7,500 SY SY + (200 SY SY) = 8,300 SY See the attached Plan Quantity Analysis and Plan Summary Sheets for the proper way to document changes to the quantities. Documentation for each project number should be kept separate for proper tracking.

11 SOLUTION TO HOMEWORK PROBLEM #1: Plan Quantity Analysis Worksheet

12 SOLUTION TO HOMEWORK PROBLEM #1 Plan Summary Box for Project 1 (FPID #: )

13 SOLUTION TO HOMEWORK PROBLEM #1 Plan Summary Box for Project 2 (FPID #: )

14 HOMEWORK PROBLEM #2 Lump Sum Reference: Module 2 - Methods of Measurement & Documentation The plans call for Clearing and Grubbing for the replacement of fence. The plan area to be cleared is 10 ft. wide on each side of the road from Station 5+00 to Station The secondary units are shown in the plans. Due to field conditions, the area increased by 618 SY beyond the planned area. The bid Lump Sum Price is $5,000 for the original limits. What is the adjusted quantity and the final dollar amount for Clearing and Grubbing?

15 SOLUTION TO HOMEWORK PROBLEM #2 Step 1: Determine the original Clearing and Grubbing plan area (Note: Double the area since clearing and grubbing is on both sides of the road). Original Plan Area = 2(10 )(4, ) 9 = 8,380 SY Step 2: Determine the revised Clearing and Grubbing plan area Additional Area = 618 SY Revised Area = 8,380 SY SY = 8,998 SY Solution: Determine the adjusted quantity and cost Adjusted Quantity = Revised Area Original Area 8,998 SY = 8,380 SY = LS Final Cost = ($5,000)(1.074 LS) = $5,370.00

16 HOMEWORK PROBLEM #3 Pay Quantity for Miscellaneous Asphalt Reference: Module 3 - Asphalt Construction plans specify asphalt will be placed around the guardrail 2 thick. Likewise, the Designer s calculations are based on a thickness of 2 under the guardrail. The area paved has the dimensions of 7,500 in length and 6 wide. There were no changes in the field. The following additional information has been given: Plan Quantity Tons = 500 Tons Tons Placed = 515 tons G mm per Specifications = G mm Design Mix 1 = 2.544; Tons Used = 284 Tons G mm Design Mix 2 = 2.564; Tons Used = 231 Tons Determine the following items: 1. Weighted G mm, 2. Adjusted Plan Quantity Tonnage 3. Maximum Allowable Tonnage (105%) 4. Pay Quantity

17 CALCULATION AREA & NOTES:

18 SOLUTION FOR HOMEWORK PROBLEM #3 1. Determine the Weighted G mm Weighted Gmm= Weighted G mm = Tons Mix 1 G mm Mix 1 +(Tons Mix 2)(Gmm Mix 2) (Tons Mix 1+Tons Mix 2) 284 tons tons (284 tons tons) Weighted G mm = Determine the Adjusted Plan Quantity (PQ) Tonnage Adjusted Plan Quantity Tonnage = (PQ Tons) (Weighted Gmm) Design Gmm PQ Tons = Original PQ (Including any Engineer Approved Quantity Change) Adjusted Plan Quantity Tonnage = (500 tons) (2.553) = Tons 3. Determine the Maximum Allowable Tonnage Maximum Allowable Tonnage = 1.05 (502.6 tons) = Tons 4. Determine the Pay Quantity The Contractor only placed 515 Tons, so they will only be paid for 515 tons.

19 HOMEWORK PROBLEM #4 Specification Superpave Asphalt Base Reference: Module 3 - Asphalt Superpave asphalt base will be used on project (FIN No ) with the following information provided: Base Group 15 Type B-12.5 The Contractor will install 9" in 3 layers Plan Quantity = 23,105 SY (No Plan Errors and No Field Revisions) G mm used for Plan Quantity determination, per Specification = Total Tons placed on the job = 11,776 Tons Unit Price = $16.65/SY Lots Placed = 3 and 3 design mixes Lot Tonnage SY CPF G mm 1 3,991 7, Mix 1 = ,989 7, Mix 2 = ,796 7, Mix 3 = The Target Spread rate is set at 330 Lbs/SY per layer (based on the Design Mix). Based upon this information please determine the following: 1. What is the Plan Quantity Area? 2. Weighted G mm 3. Adjusted Plan Quantity, tons 4. Pay Area 5. Pay Adjustment (both SY and corresponding dollar value). Will this be a negative or positive? 6. Calculate the Adjusted New Unit Prices for the CPF 7. Report on the Summary Box Sheet (show all Line Item Adjustments that will appear in SiteManager, positive and/or negative)

20 CALCULATION AREA & NOTES:

21 CALCULATION AREA & NOTES:

22 CALCULATION AREA & NOTES:

23 SOLUTION TO HOMEWORK PROBLEM #4 1. Since there were no plan errors or authorized changes, Final Plan Quantity Area = 23,105 SY 2. Determine the Tonnage-Weighted G mm Tonnage-Weighted G mm = Ton Mix 1 G = mm Mix 1 + Ton Mix 2 G mm Mix 2 +(Ton Mix 3)(Gmm Mix 3) Ton Mix 1 + Ton Mix 2 + Ton Mix 3 = = 3,991 tons ,989 tons (3,796 tons)(2.579) 3,991 tons + 3,989 tons + 3,796 tons 10,372.6 tons + 10,168.0 tons + 9,789.9 tons 11,776 tons Weighted G mm = Determine the Adjusted Plan Quantity (Plan Quantity Area) (Spread Rate per Spec 234 9) Adjusted Plan Quantity = 2,000 lb/ton Adjusted PQ = Adjusted PQ = (Plan Quantity Area) (Thickness) (Weighted Gmm) (43.3) 2,000 lbs/ton (23,105 SY) (9") (2.576) (43.3) 2,000 lbs/ton Adjusted PQ = 11,597.2 Tons 4. Determine the Pay Area Pay Area (SY) = Plan Quantity Area = 23,105 SY Actual Tonnage Placed on Project Adjusted Plan Quantity Tonnage 11,776.0 tons 11,597.2 tons Pay Area = 23,461 SY = (23,105) (1.015)

24 SOLUTION TO HOMEWORK PROBLEM #4 5. Determine the Pay Adjustment Pay Adjustment (SY) = Plan Quantity Area Actual Tonnage Placed on Project Adjusted Plan Quantity Tonnage 1 Pay Adjustment (SY) = 23,105 SY 11,776.0 tons 11,597.2 tons 1 Pay Adjustment (SY) = 356 SY Another way to calculate this is: Pay Adjustment (SY) = Pay Area (SY) Plan Quantity (SY) = 23,4561 SY 23,105 SY Pay Adjustment (SY) = SY Pay Adjustment ($$) = (356 SY) ($16.65/SY) = -$5, Determine the new Adjusted Unit Prices There are three (3) varying Composite Pay Factor s (CPF s), each requires a Unit Price Adjustment, and for SiteManager, this is what is done: Adjusted Unit Price = (Composite Pay Factor 1) (Bid Unit Price) Bid Adjusted LOT CPF Unit Price Unit Price = $ $ = $ $ = $ $0.17

25 SOLUTION TO HOMEWORK PROBLEM #4

26 SOLUTION TO HOMEWORK PROBLEM #4

27 HOMEWORK PROBLEM #5 FC-5 Open Graded Friction Course Straightedge Deficiency Reference: Module 3 - Asphalt After a straightedge test was performed, it was determined that a straightedge deficiency will be left in place at no pay. Calculate the equivalent tonnage that will be affected by this decision given the following information below. Lane Width = 12 ft. Deficient Straightedge Location = Station 1+50 to Station 1+55 Spread Rate = 75 Lbs/ SY

28 SOLUTION TO HOMEWORK PROBLEM #5 Per Specifications the penalty is applied 50 ft. each side of the deficiency; therefore the total length will be 105 ft. Length of Deficiency = STA 1+55 STA 1+50 = 5 ft Total Length of Penalty = 5 ft + 50 ft + 50 ft = 105 ft Total Tons to be deducted = (Length) (Width) (0.0044) = (105 ft) (12 ft) (0.0044) = 5.54 Tons The total tonnage to be deducted is 5.5 Tons. Note: Remember that tonnage is always rounded to the nearest tenth.

29 HOMEWORK PROBLEM #6 Miscellaneous Asphalt Reference: Module 3 - Asphalt The Contractor has placed 800 SY of Miscellaneous Asphalt around Guardrail and used 90.5 Tons of asphalt while placing a thickness of 2. Given the information below, what is the maximum tonnage that can be paid? Plan Area = 800 SY Plan Quantity Tons = 80.0 Tons Design Mix Used G mm = Design G mm (Per Specs) = 2.540

30 CALCULATION AREA & NOTES:

31 SOLUTION TO HOMEWORK PROBLEM #6 Step 1: Determine the Tonnage-Weighted G mm Tonnage-Weighted G mm = Tons Mix 1) (Gmm Mix 1) Tons Mix 1 Tonnage-Weighted G mm = 90.5 tons) (2.599) 90.5 tons = Step 2: Determine the Adjusted Plan Quantity Tonnage Adjusted Plan Quantity Tonnage = PQ Tons) (Weighted Gmm) Design Gmm Adjusted PQ Tonnage = 80.0 tons) (2.599) = 81.9 Tons Step 3: Determine the Maximum Tonnage that can be paid Maximum Tonnage to Pay = 1.05 (Adjusted Plan Quantity) = 1.05 (81.9 tons) = 86.0 Tons Solution: The Contractor placed 90.5 Tons, however, maximum tonnage that can be paid is 86.0 Tons. Note: If the Contractor is paid 90.5 tons, 4.5 tons will need to be deducted in SiteManager. (90.5 TN 86.0 TN = 4.5 TN)

32 HOMEWORK PROBLEM #7 Multi Project Asphalt Proration Reference: Module 3 - Asphalt Contract T4553 contains two projects. The total asphalt for the entire Contract is 16,000 Tons. Project 1 (FIN # ) has a bid quantity of 5,000 tons of asphalt to be placed on project. Whereas, Project 2 (FIN # ) has a bid quantity of 11,000 tons of asphalt to be placed on project. Today, 2,750 tons were place on the entire contract without being separated by project. The Project Administrator needs to separate the tonnage used for each project. What is the tonnage used on each project today?

33 SOLUTION TO HOMEWORK PROBLEM #7 Step 1: Determine the ratio of asphalt for Project 1 (FIN # ) for the entire contract Asphalt Ratio = 5,000 tons 16,000 tons = 0.31 Step 2: Determine the ratio of asphalt for Project 2 (FIN # ) for the entire contract Asphalt Ratio = 11,000 tons 16,000 tons = 0.69 Solution: Project 1 Tonnage = 0.31 (2,750 tons) = tons Project 2 Tonnage = 0.69 (2,750 tons) = 1,897.5 tons Verify: ,897.5 = 2,750 tons

34 HOMEWORK PROBLEM #8 Earthwork Volume Calculation by Average End Area Method Reference: Module 5 - Earthwork Volume (V) = (Area 1 + Area 2) (Length between Areas) 54 Given the following information, calculate the volumes Subsoil, Regular Excavation and Embankment to the nearest CY (no fractions). Subsoil Excavation Regular Excavation Embankment Station Area (SF) Volume (CY) Area (SF) Volume (CY) Area (SF) Volume (CY) Totals

35 SOLUTION TO HOMEWORK PROBLEM #8 Step 1: Determine the length between areas. Sta Sta = 50 ft Step 2: Determine volumes using the average end area formula. Subsoil = 0 CY Note: There is no area; therefore there is no volume. Regular Excavation = 14 SF + 10 SF (50 ) 54 = 22 CY Embankment = 15 SY + 21 SY (50 ) 54 = 33 CY Step 3: Fill in the table. Subsoil Excavation Regular Excavation Embankment Station Area (SF) Volume (CY) Area (SF) Volume (CY) Area (SF) Volume (CY) Totals

36 HOMEWORK PROBLEM #9 Earthwork Volume Calculation by Average End Area Method Reference: Module 5 - Earthwork Volume (V) = (Area 1 + Area 2) (Length between Areas) 54 Given the following information, calculate the volumes Subsoil, Regular Excavation and Embankment to the nearest CY (no fractions). Also determine the Final Embankment Pay Quantity. Subsoil Excavation Regular Excavation Embankment Station Area (SF) Volume (CY) Area (SF) Volume (CY) Area (SF) Volume (CY) Totals

37 CALCULATION AREA & NOTES:

38 SOLUTION TO HOMEWORK PROBLEM #9 Step 1: Determine the length between areas. Sta Sta = 100 ft Step 2: Determine volumes using the average end area formula. Subsoil Excavation = 2 SF + 2 SF (100 ) 54 = 7 CY Regular Excavation = 10 SF + 19 SF (100 ) 54 = 54 CY Embankment = 17 SF + 22 SF (100 ) 54 = 72 CY Step 3: Fill in the Table. Subsoil Excavation Regular Excavation Embankment Station Area (SF) Volume (CY) Area (SF) Volume (CY) Area (SF) Volume (CY) Totals Step 4: Determine Total Embankment Pay Quantity. Total Embankment Pay Quantity = Embankment + Subsoil Total Embankment Pay Quantity = = 79 CY

39 HOMEWORK PROBLEM #10 Earthwork Volume Calculation by Average End Area Method Reference: Module 5 - Earthwork Volume (V) = (Area 1 + Area 2) (Length between Areas) 54 Given the following information, calculate the volumes Subsoil, Regular Excavation and Embankment to the nearest CY (no fractions). Also determine the Final Embankment Pay Quantity. Subsoil Excavation Regular Excavation Embankment Station Area (SF) Volume (CY) Area (SF) Volume (CY) Area (SF) Volume (CY) Totals

40 SOLUTION TO HOMEWORK PROBLEM #10 Volume (V) = (Area 1 + Area 2) (Length between Areas) 54 Apply the steps shown in examples 8 and 9 to this example. Subsoil Excavation Regular Excavation Embankment Station Area (SF) Volume (CY) Area (SF) Volume (CY) Area (SF) Volume (CY) Totals Embankment Final Pay Quantity = 114 CY

41 HOMEWORK PROBLEM #11 Earthwork Volume Calculation by Average End Area Method Reference: Module 5 - Earthwork Volume (V) = (Area 1 + Area 2) (Length between Areas) 54 Given the following information, calculate the volumes Subsoil, Regular Excavation and Embankment to the nearest CY (no fractions). Also determine the Final Embankment Pay Quantity. Station Subsoil Excavation Area (SF) Volume (CY) Regular Excavation Area (SF) Volume (CY) Embankment Area (SF) Volume (CY)

42 SOLUTION TO HOMEWORK PROBLEM #11 Volume (V) = (Area 1 + Area 2) (Length between Areas) 54 Apply the steps shown in examples 8 and 9 to this example. Station Subsoil Excavation Area (SF) Volume (CY) Regular Excavation Area (SF) Volume (CY) Embankment Area (SF) Volume (CY) Embankment Final Pay Quantity = 76 CY

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45 HOMEWORK PROBLEM #12 Concrete Piling Reference: Module 6 Structures How many feet of piling will the Contractor be paid for this pile given the information below for a 24 concrete production pile? Remember to use the Payment Summary Sheets and refer to Design Standards Index. No Given: Authorized Length = 125 ft.; no pre-forming done There were 4 set checks performed; all within the day of initial driving Only 1 re-drive was performed The Engineer authorized a 30 ft. pile to be spliced and the splice was driven. It was cut-off after reaching bearing.

46 SOLUTION TO HOMEWORK PROBLEM #12 Concrete Piling Reference: Module 6 Structures Solution: Contractor used 125 concrete pile and the pile had 4 set checks (2 which are included in the bid price since they are within the appropriate timeframe as outlined in the Specifications); the additional 2 will add 20 LF to the Production Pile. The pile did not reach bearing, therefore the Engineer approved a 30 ft. splice. The 30 ft. of Pile + 30 ft. for material & work for splice of concrete pile will be paid for. Driving the splice will add 10 ft. of Production Pile. Total Production Pile = 235 ft.

47 HOMEWORK PROBLEM #13 Concrete Piling Reference: Module 6 Structures The Engineer of Record designed a 24 concrete production pile to be driven 130. The contractor brought in and drove a 120 ft. concrete production pile, 24 in diameter, and reached bearing. In order to meet the required elevation,hespliceda10ft.pile,as authorized by the Engineer. How many feet of piling furnished will the contractor be paid for this pile? Additional information is given below: Authorized Length = 130 ft. There were 2 set checks performed; all within the day of initial driving 60 ft of pre-forming was approved Only 1 re-drive performed Note: Remember to use the Payment Summary Sheets and refer to Design Standards Index. No

48 SOLUTION TO HOMEWORK PROBLEM #13 Concrete Piling Reference: Module 6 Structures Solution: Authorized Length = 130 ft., however the contractor brought in a 120 ft. pile instead. The 120 ft. of piling furnished will be paid. He drove the pile and reached bearing where he had to splice a 10 ft. pile to make the required elevation (which was originally authorized by the Engineer). The Contractor will also be paid for the 10 ft. pile, but not for the splice. Since the contractor knew the original length was 130 and chose to splice 10 of the total length, the Department is not responsible for paying for the splice. Note: The contractor can deliver the authorized piling length in whatever lengths he deems necessary, but no payment will be issued for the additional work for delivering those lengths unless prior approved. 2 set checks were included in the bid price. The Engineer approved the 60 ft. of preformed pile hole so 30% of each foot which is: 0.3 (60 ft)= 18 ft will be paid.

49 HOMEWORK PROBLEM #14 Concrete Piling Reference: Module 6 Structures The Engineer of Record authorized a 24 diameter concrete production pile 140 in length to be driven on a project. The Contractor, at his own option, brought in 1 at 120 feet and one at 20 feet, spliced to make 140 feet and drove the pile to bearing. Does the Department pay for the splice and driving of the splice? How many feet of piling will the contractor be paid for this pile given the additional information below? Remember to use the Payment Summary Sheets and refer to Design Standards Index. No Given: There were 2 set checks performed; all within the day of initial driving The redrive was performed after the working day following initial driving. A build-up of 4.5 ft. was required to reach the required cutoff elevation. All were authorized.

50 SOLUTION TO HOMEWORK PROBLEM #14 Concrete Piling Reference: Module 6 Structures Solution: Contractor brought in one pile at 120 feet and one at 20 feet long and spliced them to make 140 feet. The splice (materials & labor) and the driving of the splice do not qualify for payment since the Contractor chose to split the length. The 2 set checks were included in the bid price. Since the redrive and build-up were authorized, as shown in the previous table, the Department will pay for these items.

51 HOMEWORK PROBLEM #15 Concrete Piling Reference: Module 6 Structures The authorized length of a 24 concrete production pile on a project is 120, perthe Engineer of Record. The contractor, at his own option, delivered a 130 foot pile instead of the authorized 120 foot length. What is the total pile furnished that the Contractor will be paid given the additional information below? Given: The Engineer approved a preformed hole of 60 feet There were 3 set checks all within the working day following initial driving The pile was driven until it reached bearing at 120 feet. 10 feet of pile was cut off to reach the required elevation.

52 SOLUTION TO HOMEWORK PROBLEM #15 Concrete Piling Reference: Module 6 Structures Solution: The Contractor will be paid 120 ft., because that was the authorized length and all that was needed to reach bearing. The cut off of 10 ft will not be paid because the extra length was delivered at the contractor s discretion and was not authorized or needed. Preformed Pile Hole = 0.30 (60 ft) = 18 ft. 3 set-checks were within the working day following initial driving; therefore 2 are included in the bid price and the third set check will be paid as 10 ft. of production pile. No pay for cut-off since the Contractor chose to bring additional length beyond the authorized length to the job and due to Specification which doesn t allow payment for cut offs.

53 HOMEWORK PROBLEM #16 Concrete Piling Reference: Module 6 Structures The authorized length of a concrete test pile on a project is 120, per the Engineer of Record. The contractor delivered a 120 foot pile and drove it until reaching bearing. What is the total pile furnished that the contractor will be paid given the additional information below? There was no pre-forming 4 set-checks were completed; 2 on the day of initial driving and 2 on the working day following initial driving The pile was re-driven The pile reached bearing before reaching the required elevation and 5 of piling was cut off

54 SOLUTION TO HOMEWORK PROBLEM #16 Concrete Piling Reference: Module 6 Structures Solution: The Contractor furnished the authorized length of 120 ; therefore 120 will be paid. Allowable set-checks included within the bid price for test pilings include 4 from the day of initial driving to the working day following initial driving; therefore no additional pay is needed. One re-drive was required which should be paid 20. Cutoff is included in the bid price

55 HOMEWORK PROBLEM #17 Concrete Piling Reference: Module 6 Structures How many feet of piling will the contractor be paid for this pile given the information below for a steel production pipe pile? Remember to use the Payment Summary Sheets and refer to Design Standards Index. No Given: Authorized Length = 100 ft. The contractor delivered a 80 ft. pile. The Contractor also delivered a 20 ft. pile to make the 100 ft., but did not splice the piles. The contractor drove the 80 ft. pile to bearing at 75 ft and cut off the pile to the required elevation. There were 4 set checks performed; 3 on the day of initial driving and 1 on the working day following initial driving

56 SOLUTION TO HOMEWORK PROBLEM #17 Concrete Piling Reference: Module 6 Structures Since the contractor did not furnish and install the authorized 100 ft., they will only be paid the length of piling furnished and installed, which is 80 ft. For steel production piles, 2 set checks from the day of initial driving to the working day following initial driving are included in the bid price. The 2 additional set checks within this timeframe will be paid at 10 feet of production pile each. Note: If the Contractor would have spliced the 20 foot pile to the 80 foot pile and drove it, the Contractor would have been paid 100 foot of piling, delivered and furnished.

57 HOMEWORK PROBLEM #18 Concrete Piling Reference: Module 6 Structures How many feet of piling will the contractor be paid for this pile given the information below for a 24 steel production pile? Remember to use the Payment Summary Sheets and refer to Design Standards Index. No Given: Authorized Length = 80 ft. The contractor delivered two 40 ft. piles. The engineer authorized an additional 10 ft splice. The contractor drove the pile to bearing at 89 ft and cut off the pile to the required elevation. 20 ft. of preforming was authorized. There were 3 set checks performed; all within the day of initial driving

58 SOLUTION TO HOMEWORK PROBLEM #18 Concrete Piling Reference: Module 6 Structures The Contractor delivered 2 (40 ft.) piles, spliced and drove the piles. The Department will not pay for that splice and materials and labor for driving of the splice, because the contractor delivered the authorized length in 2 pieces and spliced them at his discretion. Contractor is allowed 2 set checks from the day of initial driving to the working day following initial driving. Since 10 ft. of production pile will be paid for each additional set check in the allowable timeframe, an additional 10 ft will be paid. The only authorized splice is for the additional 10 ft.. The Contractor will be paid 10 for the length of the splice and 20 ft. for the materials and labor for driving the splice. There is no payment in the specification for driving the splice.

59 HOMEWORK PROBLEM #19 Contract Time Reference: Module 7 Contract Time 1. Find the start of the Contract Time date 2. Calculate the total calendar days allowed, elapsed, underrun and overrun. 3. Calculate the amount of liquidated damages for the Contract.

60 SOLUTION TO HOMEWORK PROBLEM #19 Contract Time Reference: Module 7 Contract Time

61 HOMEWORK PROBLEM #20 Contract Time Reference: Module 7 Contract Time 1. Find the start of the Contract Time date 2. Calculate the total calendar days allowed, elapsed, underrun and overrun. 3. Calculate the amount of liquidated damages for the Contract.

62 SOLUTION TO HOMEWORK PROBLEM #20 Contract Time Reference: Module 7 Contract Time

63 HOMEWORK PROBLEM #21 Contract Time Reference: Module 7 Contract Time 1. Find the start of the Contract Time date 2. Calculate the total calendar days allowed, elapsed, underrun and overrun. 3. Calculate the amount of liquidated damages for the Contract.

64 SOLUTION TO HOMEWORK PROBLEM #21 Contract Time Reference: Module 7 Contract Time