Wall 1. indoor air film ½ gypsum board ½ sound deadening board. stud (dg. fir) w/3.5 Ins. Wood Bevel Lapped Siding (0.75 x10 ) outdoor air film

Transcription

1 Recitation 3 Heating and Cooling Load Analysis

2 U-Value Calculation lation Section View Wall 1 indoor air film ½ gypsum board ½ sound deadening board 2 x4 nominal stud (dg. fir) w/3.5 Ins. ½ Plywood (fir) Wood Bevel Lapped Siding (0.75 x10 ) outdoor air film

3 Finding Indoor Air Film Coefficient h I Indoor air film Vertical surface Film surface conductance coefficient Horizontal heat flow (S: p. 158, T4.3) Non-reflective surface h I =1.46 R=0.68 S: p. 1570, T.E. 3A

4 U-Value Calculation At Insulation At Frame Component (R I ) (R F ) Ref. indoor air film T.E.3A ½ gypsum board T.E.1 ½ Sound dead. Bd T.E.1 2x4 stud (3.5 dg. fir) n.a T.E Insulation n.a. T.E.1 ½ plywood (fir) T.E.1 Wood Siding T.E.1 outdoor air film T.E.3A Totals ΣR I ΣR F 8.63 U I U F 0.116

5 Finding Gypsum Board R-value ½ Gypsum Table 4.2 Board Thermal Properties of Typical Building and Insulating Materials R=0.45 S: p. 1549, T.E.1

6 U-Value Calculation At Insulation At Frame Component (R I ) (R F ) Ref. indoor air film T.E.3A ½ gypsum board T.E.1 ½ Sound dead. Bd T.E.1 2x4 stud (3.5 dg. fir) n.a T.E Insulation n.a. T.E.1 ½ plywood (fir) T.E.1 Wood Siding T.E.1 outdoor air film T.E.3A Totals ΣR I ΣR F 8.63 U I U F 0.116

7 Finding Sound Deadening Board R-value ½ Sound Table 4.2 Deadening Thermal Board Properties of Typical Building and Insulating Materials R=1.35 S: p. 1550, T.E.1

8 U-Value Calculation At Insulation At Frame Component (R I ) (R F ) Ref. indoor air film T.E.3A ½ gypsum board T.E.1 ½ Sound dead. Bd T.E.1 2x4 stud (3.5 dg. fir) n.a T.E Insulation n.a. T.E.1 ½ plywood (fir) T.E.1 Wood Siding T.E.1 outdoor air film T.E.3A Totals ΣR I ΣR F 8.63 U I U F 0.116

9 Finding Framing R-value Nominal 2x4 Douglas Fir stud depth is 3.5 R avg =( )/2=1.03/inch Table 4.2 Thermal Properties of Typical Building and Insulating Materials R=3.5x1.03 =3.61 S: p. 1567, T.E.1

10 U-Value Calculation At Insulation At Frame Component (R I ) (R F ) Ref. indoor air film T.E.3A ½ gypsum board T.E.1 ½ Sound dead. Bd T.E.1 2x4 stud (3.5 dg. fir) n.a T.E Insulation n.a. T.E.1 ½ plywood (fir) T.E.1 Wood Siding T.E.1 outdoor air film T.E.3A Totals ΣR I ΣR F 8.63 U I U F 0.116

11 Thermal Properties Table 35 Ins 3.5 Insulation Table 4.2 Thermal Mineral Fiber Properties of Typical Building and R=13.00 Insulating Materials S: p , T.E.1

12 U-Value Calculation At Insulation At Frame Component (R I ) (R F ) Ref. indoor air film T.E.3A ½ gypsum board T.E.1 ½ Sound dead. Bd T.E.1 2x4 stud (3.5 dg. fir) n.a T.E Insulation n.a. T.E.1 ½ plywood (fir) T.E.1 Wood Siding T.E.1 outdoor air film T.E.3A Totals ΣR I ΣR F 8.63 U I U F 0.116

13 Finding Plywood R-value ½ Plywood (fir) Table 4.2 Thermal Properties of Typical R=0.62 Building and Insulating Materials S: p. 1549, T.E.1

14 U-Value Calculation At Insulation At Frame Component (R I ) (R F ) Ref. indoor air film T.E.3A ½ gypsum board T.E.1 ½ Sound dead. Bd T.E.1 2x4 stud (3.5 dg. fir) n.a T.E Insulation n.a. T.E.1 ½ plywood (fir) T.E.1 Wood Siding T.E.1 outdoor air film T.E.3A Totals ΣR I ΣR F 8.63 U I U F 0.116

15 Finding Wood Bevel Siding R-value Wood Bevel, 0.75x10, lapped Table 4.2 Thermal Properties of Typical Building and Insulating Materials R=1.05 S: p. 1566, T.E.1

16 U-Value Calculation At Insulation At Frame Component (R I ) (R F ) Ref. indoor air film T.E.3A ½ gypsum board T.E.1 ½ Sound dead. Bd T.E.1 2x4 stud (3.5 dg. fir) n.a T.E Insulation n.a. T.E.1 ½ plywood (fir) T.E.1 Wood Siding T.E.1 outdoor air film T.E.3A Totals ΣR I ΣR F 8.63 U I U F 0.116

17 Finding Outdoor Air Film Coefficient--h O Outdoor air film Winter Wind Film surface conductance coefficient Horizontal heat flow (S: p. 158, T4.3) Non-reflective surface h O =6.0 R=0.17 S: p. 1570, T.E.3A

18 U-Value Calculation At Insulation At Frame Component (R I ) (R F ) Ref. indoor air film T.E.3A ½ gypsum board T.E.1 ½ Sound dead. Bd T.E.1 2x4 stud (3.5 dg. fir) n.a T.E Insulation n.a. T.E.1 ½ plywood (fir) T.E.1 Wood Siding T.E.1 outdoor air film T.E.3A Totals ΣR I ΣR F 7.89 U I U F 0.127

19 U-Value Overall Average At Insulation At Frame Component (R I ) (R F ) Totals ΣR I ΣR F 8.63 U I U F % framing: U AVG =0.85(0.058)+0.15(0.127)=0.0683

20 Weight/SF at Framing Density Weight Component #/cf #/sf indoor air film ½ gypsum board ½ Sound Bd Insulation (85%) Framing (15%) ½ plywood wood siding (fir) outdoor air film #/sf 7.02 Weight (#/sf)=density (#/cf) x Thickness (ft.)

21 Weighted Average Average= 0.85(6.22) (14.04) = 7.4 lbs/sf

22 Heating Load Calculation lation

23 Heating Load Example Problem Building: Office Building Location: Salt Lake City ΔT=IDBT-ODBT=68-8=60ºF 8=60 F Building: 150 x 90 (4 stories tall) U wall = Btuh/sf-ºF U roof = Btuh/sf-ºF U window = 0.46 Btuh/sf-ºF U slab = 0.16 Btuh/sf-ºF U door = 0.19 Btuh/sf-ºF door /

24 Heating Load Example Problem Determine Building Envelope Areas (SF) Building: 150 x 90 (4 stories) N E S W Gross Wall 4,100 7,200 4,300 7,100 Windows 1,000 1,980 1,208 1,860 Doors Net Wall 3,082 5,184 3,074 5,204 Roof Floor Slab 12,825 sf 13,500 sf

25 Heating Loads Insert roof values , ,319 32,319 N , ,986 E , ,796 S , ,960 W , ,861 53,603 Insert wall values N , ,600 E , ,648 H=18630 Insert glass values Insert door values Insert floor values S , ,341 W , , , ,231 1,231 N/A N/A N/A N/A SR-3

26 Slab to Soil Losses Q=U slab x 0.5 x A slab x (T I -T GW ) T I =Indoor Air Temperature e T GW =Ground Water Temperature Ground Water= 53ºF ΔT=68ºF-53ºF=15ºF F F F

27 Heating Loads Insert floor values , ,319 32,319 N , ,986 E , ,796 S , ,960 W , ,861 53,603 N , ,600 E , ,648 H=18630 S , ,341 W , , , ,231 1,231 N/A N/A N/A N/A , ,200 SR-3

28 Edge Losses Method I Determine F 2 based on 2 heating degree days S: p. 1582, T.E.11

29 Heating Degree ee Days Salt Lake City HDD 65 =5983 S: p. 1524, T.C.15

30 Edge Losses Method I Interpolate to find F 2 at 5983 DD F 2? S: p. 1582, T.E. 11

31 Interpolate to Find F 2 Find difference in Degree Days: = =2083 Find difference in F 2 : F 2?-0.50=x =0.06 Set up proportion, solve for x: 633/2083=x/0.06 x=0.018 F 2?-0.50= F 2?=0.518

32 Edge Losses Method I Interpolate to find F 2 at 5983 DD F 2 = S: p. 1582, T.E.11

33 Heating Loads Insert floor values , ,319 32,319 N , ,986 E , ,796 S , ,960 W , ,861 53,603 N , ,600 E , ,648 H=18630 S , ,341 W , , , ,231 1,231 N/A N/A N/A N/A , , ,918 31,118 SR-3

34 Ventilation Load Sensible People: 13,500 x 4 flrs x 5persons/1000sf=270 Ventilation: 17 cfm/person = 4,590 cfm 4,590 cfm x 60min/hr = 274,400 cfh

35 Heating Loads Input Ventilation Load Sensible , ,319 32,319 N , ,986 E , ,796 S , ,960 W , ,861 53,603 N , ,600 E , ,648 H=18630 S , ,341 W , , , ,231 1,231 N/A N/A N/A N/A , , ,918 31, , SR-3

36 Ventilation Load Latent Determine ΔW W I = #H 2 O/#dry air -W O = #H 2 O/#dry air ΔW= #H 2 O/#dry air

37 Heating Loads Input Ventilation Load Latent , ,319 32,319 N , ,986 E , ,796 S , ,960 W , ,861 53,603 N , ,600 E , ,648 H=18630 S , ,341 W , , , ,231 1,231 N/A N/A N/A N/A , , ,918 31, , SR-3 275, ,

38 Heating Load , ,319 32,319 N , ,986 E , ,796 S , ,960 Total Load W , ,861 53, N , ,600 E , ,648 H=18630 S , , , 624 Btuh W , , , or MBH ,231 1,231 N/A N/A N/A N/A , , ,918 31, , SR-3 275, , ,

39 Cooling Load Calculation lation

40 Summer Design Conditions Design Dry Bulb Temperature Mean Daily Range S: p. 1496, T.B1

41 Cooling Load Example Problem Building: Office Building Location: Salt Lake City Building: 150 x 90 (4 stories tall) U wall = Btuh/sf-ºF U roof = Btuh/sf-ºF U window = 0.46 Btuh/sf-ºF U slab = 0.16 Btuh/sf-ºF U door = 0.19 Btuh/sf-ºF door /

42 Cooling Load Example Problem Determine Building Envelope Areas (SF) Building: 150 x 90 (4 stories) N E S W Gross Wall 4,100 7,200 4,300 7,100 Windows 1,000 1,980 1,208 1,860 Doors Net Wall 3,082 5,184 3,074 5,204 Roof Floor Slab 12,825 sf 13,500 sf

43 Determine Design Equivalent Temperature Difference (DETD) Roof Construction ti type: Dark color, vented, ceiling Design temperature: 95ºF Mean daily range: 32ºF L: 0-16ºF M: 16-25ºF H: 25+ºF DETD=39.0ºF S: p. 1613, T.F.5

44 0.042 Cooling Loads ,007 21,007 Insert roof values SR-3

45 Determine Design Equivalent Temperature Difference (DETD) Wall Construction ti type (see given) Design temperature: 95ºF Mean daily range: 32ºF L: 0-16ºF M: 16-25ºF H: 25+ºF DETD=11.3ºF S: p. 1613, T.F.5

46 0.042 Cooling Loads Insert roof values ,007 21,007 N , ,881 E , ,163 S , ,876 W , ,175 10,095 Insert wall values SR-3

47 Determine Window DCLF Glazing Type Design Temperature Shading Orientation S: p. 1615, T.F.6

48 0.042 Cooling Loads Insert roof values ,007 21,007 N , ,881 E , ,163 S , ,876 W , ,175 10,095 Insert wall values N 1, ,000 Insert glass values E 1, ,300 S 1, ,160 W 1, ,100 H , ,010 SR-3

49 Number of People and Ventilation 270 people 4590 cfm

50 Ventilation Load Sensible CLF Design Temperature: 95ºF Commercial Building: Ventilation S: p. 1617, T.F.7

51 0.042 Cooling Loads Insert roof values ,007 21,007 N , ,881 E , ,163 S , ,876 W , ,175 10,095 Insert wall values N 1, ,000 Insert glass values E 1, ,300 S 1, ,160 W 1, ,100 H , ,010 Insert outdoor air N/A N/A N/A values 4, , ,980 SR-3

52 People Sensible Gain Determine number of people: 270 Activity level: moderately active office work S: p. 1617, T.F.8

53 0.042 Cooling Loads Insert roof values ,007 21,007 N , ,881 E , ,163 S , ,876 W , ,175 10,095 Insert wall values N 1, ,000 Insert glass values E 1, ,300 S 1, ,160 W 1, ,100 H , ,010 Insert outdoor air N/A N/A N/A values 4, , ,980 Insert people values ,500 SR-3

54 Lighting Load Lighting load: 1.5 w/sf Equipment load: 0.5 w/sf

55 0.042 Cooling Loads Insert roof values ,007 21,007 N , ,881 E , ,163 S , ,876 W , ,175 10,095 Insert wall values N 1, ,000 Insert glass values E 1, ,300 S 1, ,160 W 1, ,100 H , ,010 Insert outdoor air N/A N/A N/A values 4, , ,980 Insert people values Insert lighting values ,500 54, ,453 54, , ,104 Insert equipment values SR-3

56 Cooling Loads Sensible Heat Gain: 896,536 Btuh Latent Heat Gain (20%): 160,839 Btuh ,007 21,007 N , ,881 E , ,163 S , ,876 W , ,175 10,095 N 1, ,000 E 1, ,300 S 1, ,160 W 1, ,100 H , ,010 N/A N/A N/A Total Heat Gain: 965,035 Btuh or 80.4 Tons 4, , , ,500 54, ,453 54, , , Tons=Q/12,000 SR , , ,

57 Insert Microclimate critiques here Insert Exam results here