Figure: Grid or Waffle slab

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Two Way Beam Supported Slab References: 1. Design of. Reinforced Concrete, 2014, 9 th Edition, ACI 318-11 Code Edition, by Jack C. McCormac. Clemson University. Russell H. Brown. Clemson University 2. Design of Concrete Structures 14th Edition, 2009, by Arthur H. Nilson. Professor Emeritus. College of Engineering. Cornell University, David Darwin (University of Kansas), Charles Dolan (University of Wyoming) 3. Others Types of slabs Figure: Grid or Waffle slab One way slab Two way slab 1

2

Figure: Two way slab (a) Bending of center strip, (b) grid model Figure: Moment variations of a uniformly loaded slab with simple supports on four sides. Two way Slabs with Beams on All Sides: The parameter used to define the relative stiffness of the beam and slab spanning in either direction is α, calculated from α = E cb I b E cs I s. In which E cb and E cs are the modulus of elasticity of the beam and slab concrete (usually the same) and I b and I s are the moments of inertia of the effective beam and the slab. Then α m is defined as the average value of α for all beams on the edges of a given panel. Minimum Thickness for two way slabs: 3

Question: What are the ACI guidelines for the minimum thickness, h for slabs with beams spanning between the supports on all sides? span **-*-*-*-*-*-*-*-*--*-* 4

(1) According to ACI code 9.5.3.3, for α m equal to or less than 0.2, the minimum thickness of ACI Table 9.5(c): shall apply. ACI Table 9.5(c): Minimum thickness of slabs without interior beams Without Drop Panels With Drop Panels Yield Stress f y, psi Exterior Panels Interior Panels Exterior Panels Without Edge Beams With Edge Beams a Without Edge Beams With Edge Beams a Interior Panels 40,000 60,000 75,000 l n /33 l n /30 l n /28 l n /36 l n /33 l n /31 l n /36 l n /33 l n /31 l n /36 l n /33 l n /31 l n /40 l n /36 l n /34 l n /40 l n /36 l n /34 a Slabs with beams along exterior edges. The value of α for the edge beam shall not be less than 0.8. (2) For α m greater than 0.2 but not greater than 2.0, the slab thickness must not be less than h= l fy n [0.8+ 200,000 ] 36+5β(α m 0.2) and not less than 5.0 inch.. (01) 5

(3) For α m greater than 2.0, the thickness must not be less than h= l fy n [0.8+ 200,000 ] 36+9β where l n = clear span in long direction, inches and not less than 3.5 inch.. (02) α m = average value of α for all beams on edges of a panel. β= ratio of clear span in long direction to clear span in short direction. fy = Yield strength of steel in psi Note: At discontinuous edges, an edge beam must be provided with a stiffness ratio α not less than 0.8; otherwise the minimum thickness provided by Eq. (01) or (02) must be increased by at least 10 percent in the panel with the discontinuous edge. Additional Notes: In all cases, slab thickness less than stated minimum may be used if it can be shown by computation that deflections will not exceed the limit values of ACI Table 9.5 (b). ACI Table 9.5 (b): Maximum allowable computed deflections Type of member Deflection to be considered Deflection Limitation Flat roofs not supporting or attached to nonstructural elements likely to be damaged by large deflections Floors not supporting or attached to nonstructural elements likely to be damaged by large deflections Roof or floor construction supporting or attached to nonstructural elements likely to be damaged by large deflections Roof or floor construction supporting or attached to nonstructural elements not likely to be damaged by large deflections Immediate deflection due to the live load (LL) Immediate deflection due to the live load (LL) That part of the total deflection occurring after attachment of the nonstructural elements (sum of the longtime deflection due to all sustained loads and the immediate deflection due to any additional live load) l 180 l 360 l 480 l 240 6

Minimum Thickness h(inches) 14 13 12 Flat Plate With Spandrel Beams* and Flat Slab Flat Plate With Spandrel Beams* 11 10 9 Flat Plate 8 7 Two Way Beams Supported Slab(β=1) 6 5 Two Way Beam Supported Slab (β=2) 4 3 10 15 20 25 30 35 40 Longer Clear Span (ft) Finding the slab thickness for two way slab with edge beams Approximate Alternate Method for determining the slab thickness for two way slab with edge beams For grade 60 steel, thickness, h, inches = P /160 [note: P=, Perimeter in inches] 7

Example: The two-way slab shown in Figure below has been assumed to have a thickness of 7 in. Section A A in the figure shows the beam cross section. Check the ACI equations to determine if the slab thickness is satisfactory for an interior panel. f c = 3000 psi, fy = 60,000 psi, and normal-weight concrete. Solution: 8

9

The following example was done by Mr. Naim Hassan, 3 rd Year 2 nd Semester Student of CE Dept., AUST 10

Calculation of Inertia for T beam-example: Alternate Design: Design Procedure of Two-way Slabs using ACI Moment Coefficients: Step 01: Determination of thickness of the slab panel. Determine the thickness of the slab panel using previous article. Step 02: Calculation of factored load. W u = 1.2*DL+1.6*LL where DL= Total dead load (i.e.: Slab self weight, Floor finish, Partition wall, Plaster etc.) LL= Live load. Step 03: Determination of moment coefficients. m= A B where A= Shorter length of the slab. B= Longer length of the slab. Case type is identified from end condition. Using the value of m corresponding moment coefficients are obtained for respective case type from corresponding tables. The co-efficients are: C A neg and C B neg C A DL pos and C B DL pos C A LL pos and C B LL pos 11

Table for C A neg and C B neg 12

Table 04: Table for C A DL pos and C B DL pos 13

Table: Table for C A LL pos and C B LL pos 14

Step 04: Calculation of moments. Positive moments: +M A = C A DL W DL L A 2 + C A LL W LL L A 2 ; +M B = C B DL W DL L B 2 + C B LL W LL L B 2. Negative Moments: -M A = C A, neg W T L A 2 ; -M B = C A, neg W T L B 2 ; W DL L A 2 + C A LL W LL W LL =Uniform Live load per unit area, W DL =Uniform Dead load per unit area W T = Total Uniform load per unit area = W LL + W DL Start with Max moment, M then, M A s =.9 fy (d a 2 ) Now, find a = As fy 0.85 f c b Then, do at least another trial, with new a, and find area of steel. Last Updated: May 27, 2016 15