1 Chapter 9A Process Capability & SPC
2 OBJECTIVES Process Variation Process Capability Process Control Procedures Variable data Attribute data Acceptance Sampling Operating Characteristic Curve
3 Basic Forms of Variation Assignable variation is caused by factors that can be clearly identified and possibly managed Example: A poorly trained employee that creates variation in finished product output. Common variation is inherent in the production process Example: A molding process that always leaves burrs or flaws on a molded item.
Taguchi s View of Variation 4 Traditional view is that quality within the LS and US is good and that the cost of quality outside this range is constant, where Taguchi views costs as increasing as variability increases, so seek to achieve zero defects and that will truly minimize quality costs. High High Incremental Cost of Variability Incremental Cost of Variability Zero Zero Lower Spec Target Spec Upper Spec Lower Spec Target Spec Upper Spec Traditional View Taguchi s View
Process Capability 5 Process limits Specification limits How do the limits relate to one another?
6 Process Capability Index, C pk Capability Index shows how well parts being produced fit into design limit specifications. C pk = min X LTL UTL - X or 3 3 As a production process produces items small shifts in equipment or systems can cause differences in production performance from differing samples. Shifts in Process Mean
Process Capability A Standard Measure of How Good a Process Is. 7 A simple ratio: Specification Width Actual Process Width Generally, the bigger the better.
8 Process Capability C pk Min X LTL UTL X ; 3 3 This is a one-sided Capability Index Concentration on the side which is closest to the specification - closest to being bad
Coffee Bean Bag Example 9 Ron Valdez Café roasts and nationally distributes 16 ounce bags of coffee beans. The Omaha World Herald has just published an article that claims that the bags frequently have less than 15 ounces of coffee beans in out 16 ounce bags. Let s assume that the government says that we must be within ± 5 percent of the weight advertised on the bag. Upper Tolerance Limit = 16 +.05(16) = 16.8 ounces Lower Tolerance Limit = 16.05(16) = 15.2 ounces We go out and buy 1,000 bags of coffee beans and find that they weight an average of 16.102 ounces with a standard deviation of.629 ounces.
Cereal Box Process Capability 10 Specification or Tolerance Limits Upper Spec = 16.8 oz Lower Spec = 15.2 oz Observed Weight Mean = 16.102 oz Std Dev =.629 oz C pk X Min LTL UTL X ; 3 3 16.102 15.2 16.8 16.102 Min ; 3(.629) 3(.629) C pk C pk Min.478;.370 C pk.370
11 What does a C pk of.370 mean? An index that shows how well the units being produced fit within the specification limits. This is a process that will produce a relatively high number of defects. Many companies look for a C pk of 1.3 or better 6-Sigma company wants 2.0! Cpk < 1 The process is not capable Cpk = 1 The process is just capable Cpk > 1 The process is capable
Types of Statistical Sampling 12 Attribute (Go or no-go information) Defectives refers to the acceptability of product across a range of characteristics. Defects refers to the number of defects per unit which may be higher than the number of defectives. p-chart application
Types of Statistical Sampling 13 Variable (Continuous) Usually measured by the mean and the standard deviation. X-bar and R chart applications
Statistical Process Control (SPC) Charts Normal Behavior UCL LCL 14 UCL 1 2 3 4 5 6 Samples over time Possible problem, investigate LCL UCL 1 2 3 4 5 6 Samples over time Possible problem, investigate LCL 1 2 3 4 5 6 Samples over time
15 Control Limits are based on the Normal Curve x -3-2 -1 m 0 1 2 3 z Standard deviation units or z units.
Control Limits 16 We establish the Upper Control Limits (UCL) and the Lower Control Limits (LCL) with plus or minus 3 standard deviations from some x-bar or mean value. Based on this we can expect 99.7% of our sample observations to fall within these limits. LCL 99.7% UCL x
17 Example of Constructing a p-chart: Required Data Sample Number Number of Samples 1 100 4 2 100 2 3 100 5 4 100 3 5 100 6 6 100 4 7 100 3 8 100 7 9 100 1 10 100 2 11 100 3 12 100 2 13 100 2 14 100 8 15 100 3 Number of defects found in each sample
18 Statistical Process Control Formulas: Attribute Measurements (p-chart) Given: p = Total Number of Defectives Total Number of Observations s p = p (1- p) n Compute control limits: UCL = p + z s LCL = p - z s p p
19 Example of Constructing a p-chart: Step 1 1. Calculate the sample proportions, p (these are what can be plotted on the p-chart) for each sample Sample n Defectives p 1 100 4 0.04 2 100 2 0.02 3 100 5 0.05 4 100 3 0.03 5 100 6 0.06 6 100 4 0.04 7 100 3 0.03 8 100 7 0.07 9 100 1 0.01 10 100 2 0.02 11 100 3 0.03 12 100 2 0.02 13 100 2 0.02 14 100 8 0.08 15 100 3 0.03
20 Example of Constructing a p-chart: Steps 2&3 2. Calculate the average of the sample proportions p = 55 1500 = 0.036 3. Calculate the standard deviation of the sample proportion s p = p (1- p) n =.036(1-.036) 100 =.0188
21 Example of Constructing a p-chart: Step 4 4. Calculate the control limits UCL = p + z LCL = p - z s s.036 3(.0188) p p UCL = 0.0924 LCL = -0.0204 (or 0)
Example of Constructing a p-chart: Step 5 22 5. Plot the individual sample proportions, the average of the proportions, and the control limits 0.16 0.14 0.12 0.1 UCL p 0.08 0.06 0.04 0.02 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Observation LCL
Example of x-bar and R Charts: Required Data 23 Sample Obs 1 Obs 2 Obs 3 Obs 4 Obs 5 1 10.68 10.689 10.776 10.798 10.714 2 10.79 10.86 10.601 10.746 10.779 3 10.78 10.667 10.838 10.785 10.723 4 10.59 10.727 10.812 10.775 10.73 5 10.69 10.708 10.79 10.758 10.671 6 10.75 10.714 10.738 10.719 10.606 7 10.79 10.713 10.689 10.877 10.603 8 10.74 10.779 10.11 10.737 10.75 9 10.77 10.773 10.641 10.644 10.725 10 10.72 10.671 10.708 10.85 10.712 11 10.79 10.821 10.764 10.658 10.708 12 10.62 10.802 10.818 10.872 10.727 13 10.66 10.822 10.893 10.544 10.75 14 10.81 10.749 10.859 10.801 10.701 15 10.66 10.681 10.644 10.747 10.728
Example of x-bar and R charts: Step 1. Calculate sample means, sample ranges, mean of means, and mean of ranges. 24 Sample Obs 1 Obs 2 Obs 3 Obs 4 Obs 5 Avg Range 1 10.682 10.689 10.776 10.798 10.714 10.732 0.116 2 10.787 10.86 10.601 10.746 10.779 10.755 0.259 3 10.78 10.667 10.838 10.785 10.723 10.759 0.171 4 10.591 10.727 10.812 10.775 10.73 10.727 0.221 5 10.693 10.708 10.79 10.758 10.671 10.724 0.119 6 10.749 10.714 10.738 10.719 10.606 10.705 0.143 7 10.791 10.713 10.689 10.877 10.603 10.735 0.274 8 10.744 10.779 10.11 10.737 10.75 10.624 0.669 9 10.769 10.773 10.641 10.644 10.725 10.710 0.132 10 10.718 10.671 10.708 10.85 10.712 10.732 0.179 11 10.787 10.821 10.764 10.658 10.708 10.748 0.163 12 10.622 10.802 10.818 10.872 10.727 10.768 0.250 13 10.657 10.822 10.893 10.544 10.75 10.733 0.349 14 10.806 10.749 10.859 10.801 10.701 10.783 0.158 15 10.66 10.681 10.644 10.747 10.728 10.692 0.103 Averages 10.728 0.220400
Example of x-bar and R charts: Step 2. Determine Control Limit Formulas and Necessary Tabled Values 25 x Chart Control Limits UCL = x + A R LCL = x - A R R Chart Control Limits UCL = D R LCL = D R 3 4 2 2 From Exhibit TN8.7 n A2 D3 D4 2 1.88 0 3.27 3 1.02 0 2.57 4 0.73 0 2.28 5 0.58 0 2.11 6 0.48 0 2.00 7 0.42 0.08 1.92 8 0.37 0.14 1.86 9 0.34 0.18 1.82 10 0.31 0.22 1.78 11 0.29 0.26 1.74
26 Example of x-bar and R charts: Steps 3&4. Calculate x-bar Chart and Plot Values Means UCL = x + A LCL = x - A 10.90 2 2 R 10.728.58(0.2204) = 10.856 R 10.728-.58(0.2204) = 10.601 10.85 10.80 UCL 10.75 10.70 10.65 10.60 LCL 10.55 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Example of x-bar and R charts: Steps 5&6. Calculate R-chart and Plot Values 27 UCL = D LCL = D 4 3 R (2.11)(0.2204) R (0)(0.2204) 0 0.46504 R 0.80 0.70 0.60 0.50 0.40 0.30 0.20 0.10 0.00 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Sample UCL LCL
28 Basic Forms of Statistical Sampling for Quality Control Acceptance Sampling is sampling to accept or reject the immediate lot of product at hand Statistical Process Control is sampling to determine if the process is within acceptable limits
Acceptance Sampling 29 Purposes Determine quality level Ensure quality is within predetermined level Advantages Economy Less handling damage Fewer inspectors Upgrading of the inspection job Applicability to destructive testing Entire lot rejection (motivation for improvement)
Acceptance Sampling (Continued) 30 Disadvantages Risks of accepting bad lots and rejecting good lots Added planning and documentation Sample provides less information than 100-percent inspection
Acceptance Sampling: Single Sampling Plan 31 A simple goal Determine (1) how many units, n, to sample from a lot, and (2) the maximum number of defective items, c, that can be found in the sample before the lot is rejected
Risk 32 Acceptable Quality Level (AQL) Maximum acceptable percentage of defectives defined by producer. The a (Producer s risk) is the probability of rejecting a good lot Lot Tolerance Percent Defective (LTPD) Percentage of defectives that defines consumer s rejection point. The (Consumer s risk) is the probability of accepting a bad lot
Probability of acceptance Operating Characteristic Curve 33 The OCC brings the concepts of producer s risk, consumer s risk, sample size, and maximum defects allowed together 1 0.9 a =.05 (producer s risk) 0.8 0.7 n = 99 0.6 c = 4 0.5 0.4 0.3 =.10 (consumer s risk) 0.2 0.1 0 1 2 3 4 5 6 7 8 9 10 11 12 AQL LTPD Acceptable Quality Level Lot Tolerance Percent defective The shape or slope of the curve is dependent on a particular combination of the four parameters
34 Example: Acceptance Sampling Problem Zypercom, a manufacturer of video interfaces, purchases printed wiring boards from an outside vender, Procard. Procard has set an acceptable quality level of 1% and accepts a 5% risk of rejecting lots at or below this level. Zypercom considers lots with 3% defectives to be unacceptable and will assume a 10% risk of accepting a defective lot. Develop a sampling plan for Zypercom and determine a rule to be followed by the receiving inspection personnel.
35 Example: Step 1. What is given and what is not? In this problem, Acceptable Quality Level, AQL = 0.01 Tolerance Percent Defective, LTPD = 0.03 Producer s risk, a = 0.05 Consumer s risk, = 0.10 You need c and n to determine your sampling plan
36 Example: Step 2. Determine c First divide LTPD by AQL. LTPD AQL.03.01 3 Then find the value for c by selecting the value in the approprate table n AQL column that is equal to or just greater than the ratio above. Sample Plan table for a 0.05, 0.10 c LTPD/AQL n AQL c LTPD/AQL n AQL 0 44.890 0.052 5 3.549 2.613 1 10.946 0.355 6 3.206 3.286 2 6.509 0.818 7 2.957 3.981 3 4.890 1.366 8 2.768 4.695 4 4.057 1.970 9 2.618 5.426
Example: Step 3. Determine Sample Size 37 Now given the information below, compute the sample size in units to generate your sampling plan c 6, from Table n AQL 3.286, from Table AQL.01, given in problem n AQL / AQL 3.286 /.01 329 (always round up) 328.6 Sampling Plan: Take a random sample of 329 units from a lot. Reject the lot if more than 6 units are defective.