BIOLOGY/HUMAN BIOLOGY BY1

Similar documents
BIOLOGY/HUMAN BIOLOGY BY1

Cell Division. Use Target Reading Skills. This section explains how cells grow and divide.

DNA STRUCTURE. Nucleotides: Nitrogenous Bases (Carry the Genetic Code) Expectation Sheet: DNA & Cell Cycle. I can statements: Basic Information:

Cells and Tissues. Overview CELLS

Cell Biology Homework

test 7 3. What is the main function of a vacuole in a cell?

What is DNA??? DNA = Deoxyribonucleic acid IT is a molecule that contains the code for an organism s growth and function

Chapter 3. DNA Replication & The Cell Cycle

Genetics and Heredity. Mr. Gagnon

2. The instructions for making a protein are provided by a gene, which is a specific segment of a molecule.

From Gene to Protein Transcription and Translation

DNA DNA Profiling 18. Discuss the stages involved in DNA profiling 19. Define the process of DNA profiling 20. Give two uses of DNA profiling

CELLULAR PROCESSES; REPRODUCTION. Unit 5

1. DNA, RNA structure. 2. DNA replication. 3. Transcription, translation

Reinforcement. Cells and Life CHAPTER 1 LESSON 1

Nucleic acids deoxyribonucleic acid (DNA) ribonucleic acid (RNA) nucleotide

From Gene to Protein Transcription and Translation i

Biology Assessment Unit AS 1

From Gene to Protein via Transcription and Translation i

Nucleic acids. What important polymer is located in the nucleus? is the instructions for making a cell's.

1. In a microscope, the ocular (eyepiece) is used to A. look through B. direct light to the slide C. adjust the focus D.

Division Ave. High School Ms. Foglia AP Biology. Nucleic acids. AP Biology Nucleic Acids. Information storage

1.5 Nucleic Acids and Their Functions Page 1 S. Preston 1

A Level. A Level Biology. Cells, Microscopes, Cell Cycle and Immunity Questions. AQA, OCR, Edexcel. Name: Total Marks: Page 1

Thursday 26 May 2016 Afternoon Time allowed: 1 hour 30 minutes

Name: Date: Pd: Nucleic acids

Thr Gly Tyr. Gly Lys Asn

Protein Synthesis & Gene Expression

Central Dogma. 1. Human genetic material is represented in the diagram below.

10-2 Cell Division (Pages )

DNA. translation. base pairing rules for DNA Replication. thymine. cytosine. amino acids. The building blocks of proteins are?

Page 1. Name: 1) Which letter indicates a cell structure that directly controls the movement of molecules into and out of the cell?

Nucleic acids AP Biology

36. The double bonds in naturally-occuring fatty acids are usually isomers. A. cis B. trans C. both cis and trans D. D- E. L-

Bundle 5 Test Review

Zool 3200: Cell Biology Exam 3 3/6/15

Transcription. Unit: DNA. Central Dogma. 2. Transcription converts DNA into RNA. What is a gene? What is transcription? 1/7/2016

Discuss the ethical considerations that must be taken into account when using embryonic stem cells for research.

Gene Expression Translation U C A G A G

Section 10. Junaid Malek, M.D.

DNA, Replication and RNA

translation The building blocks of proteins are? amino acids nitrogen containing bases like A, G, T, C, and U Complementary base pairing links

Chapter 2 DNA extended response [108 marks]

DNA Begins the Process

From DNA to Protein Structure and Function

Key Concept Translation converts an mrna message into a polypeptide, or protein.

Bio 101 Sample questions: Chapter 10

Prokaryotic Transcription

Daily Agenda. Warm Up: Review. Translation Notes Protein Synthesis Practice. Redos

This is the knowledge that you should understand upon completing this section:

AQA Qualifications AS Biology. Paper 2 Mark scheme. 7401/2 Specimen Paper (set 2) Version of 15

Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level

STUDY GUIDE SECTION 10-1 Discovery of DNA

Biology Lecture 2 Genes

Chapter 2 Molecules to enzymes - Short answer [72 marks]

7.014 Quiz II 3/18/05. Write your name on this page and your initials on all the other pages in the space provided.

UNIT 4. DNA, RNA, and Gene Expression

NUCLEUS. Fig. 2. Various stages in the condensation of chromatin

Chapter 13 - Concept Mapping

Chapter 8: DNA and RNA

Total Test Questions: 66 Levels: Grades Units of Credit: 1.0 STANDARD 2. Demonstrate appropriate use of personal protective devices.

Flow of Genetic Information

Chapter 2 - DNA MC [37 marks]

Multiple choice questions (numbers in brackets indicate the number of correct answers)

GAUTENG DEPARTMENT OF EDUCATION SENIOR SECONDARY INTERVENTION PROGRAMME. LIFE SCIENCE Grade 12 Session 9: Nucleic Acids DNA and RNA (LEARNER NOTES)

AS Biology Syllabus 9700 Unit 3: Enzymes, DNA and Protein Synthesis

DNA & Protein Synthesis #21

GENETICS. I. Review of DNA/RNA A. Basic Structure DNA 3 parts that make up a nucleotide chains wrap around each other to form a

DNA Structure & the Genome. Bio160 General Biology

Coimisiún na Scrúduithe Stáit State Examinations Commission BIOLOGY ORDINARY LEVEL

DNA & Protein Synthesis UNIT D & E

DNA is a functional genetic material as it:

DNA: The Molecule of Heredity How did scientists discover that genes are made of DNA?

Folding simulation: self-organization of 4-helix bundle protein. yellow = helical turns

DNA - The Double Helix

The common structure of a DNA nucleotide. Hewitt

Replication Review. 1. What is DNA Replication? 2. Where does DNA Replication take place in eukaryotic cells?

DNA - The Double Helix

CHAPTER 11 DNA NOTES PT. 4: PROTEIN SYNTHESIS TRANSCRIPTION & TRANSLATION

DNA - The Double Helix

BIOLOGY LTF DIAGNOSTIC TEST DNA to PROTEIN & BIOTECHNOLOGY

Gene Expression REVIEW Packet

1. Describe the structure of DNA. Be sure to include what forms the skeleton and how are the strands held together? 2. Compare and contrast

Molecular Biology of the Gene

Biomolecules: lecture 6

11 questions for a total of 120 points

Review of ORGANIC CHEMISTRY

DNA Replication and Protein Synthesis

THE COMPONENTS & STRUCTURE OF DNA

Chapter 1 Structure of Nucleic Acids DNA The structure of part of a DNA double helix

Fig. 16-7a. 5 end Hydrogen bond 3 end. 1 nm. 3.4 nm nm

Begin with the supplemental experiment handout and get all experiments set up first before beginning slide and model observations in Exercise 4.

Covalently bonded sugar-phosphate backbone with relatively strong bonds keeps the nucleotides in the backbone connected in the correct sequence.

Regents Biology REVIEW 5: GENETICS

Reproduction, Heredity, & Molecular Genetics. A. lipids B. amino acids C. nucleotides D. polysaccarides

Nucleic Acids: DNA and RNA

DNA - The Double Helix

Transcription:

andidate Name entre Number andidate Number 2 GE AS/A level 1071/01 BILGY/UMAN BILGY BY1 A.M. TUESDAY, 12 January 2010 1 1 2 hours For s use Question Maximum Mark 1 6 2 6 3 11 4 11 5 12 6 14 7 10 Total 70 Mark Awarded W10 1071 01 1 INSTRUTINS T ANDIDATES Write your name, centre number and candidate number in the spaces at the top of this page. Answer all questions. Write your answers in the spaces provided in this booklet. INFRMATIN FR ANDIDATES The number of marks is given in brackets at the end of each question or part-question. You are reminded of the necessity for good English and orderly presentation in your answers. The quality of written communication will affect the awarding of marks. JD*(W10-1071-01)

2 1. Two types of nucleic acid, DNA and RNA are found in cells. Statements in the table, may apply to DNA, RNA or both. omplete the table by putting a tick ( ) if the statement is true or a cross ( ) if the statement is not true. [6] ontains a pentose sugar Found in the nucleus Thymine is never present onsists of a double helix Molecules short lived Associated with ribosomes DNA RNA (Total 6 marks) 2. The table below describes structural features and functions of some of the organelles found in eukaryotic cells. omplete the table. [6] rganelle Structural feature Function of feature Nucleus Golgi body Nucleolus Inner membrane folded into cristae Vesicle containing hydrolytic enzymes ell lysis (Total 6 marks)

3 3. The diagram below shows a biosensor that uses the enzyme urease to measure urea in either the blood or urine. display amplifier transducer/electrode N 4 + ammonium ions molecules of other solutes immobilised urease partially permeable membrane urea molecules W10 1071 01 3 (a) (i) Name one method that could be used to immobilise the urease. [1] (ii) State three advantages of using immobilised enzymes. [3] (b) (i) Describe the function of the partially permeable membrane in this biosensor. [2] (ii) With reference to the diagram, describe the role of this transducer. [2] Turn over.

4 (c) If the biosensor was used to test two blood samples, explain why the temperature of the two samples should be the same. [2]......... (d) Name a medical condition which a biosensor can detect. [1]... (Total 11 marks) 4. The drawing shows a simplified diagram of the cell cycle. The size of each segment indicates the relative length of each phase. prophase metaphase anaphase telophase interphase (a) (i) Draw an arrow on the diagram to show the correct sequence of events in the cycle. [1] (ii) n the diagram add a segment to show the point at which cell division (cytokinesis) occurs. [1] (b) List four events that occur during interphase. [4]............

5 (c) Name the stage of mitosis where each of the following occurs. (i) hromatids line up at the equator. [1] (ii) entromeres split. [1] (iii) Spindle fibres contract and shorten. [1] (iv) hromosomes are first visible as a pair of chromatids. [1] (v) Nuclear membrane reforms. [1] (Total 11 marks) W10 1071 01 5 Turn over.

6 5. The diagram shows cells taken from the stem of a plant. ells A, B and are adjacent cells and the figures give the water potential Ψ of each cell. A = 400kPa B = 380kPa = 360kPa (a) (i) Draw arrows on the diagram to show the overall direction of water movement between these three cells. [1] (ii) Explain your answer in terms of water potential. [2] (b) The diagram below shows two plant cells, X and Y as seen through a microscope. The figures show the solute potential Ψs and the pressure potential Ψp for both cells and the water potential Ψ for cell Y. ell X ell Y Ψp = 1000kPa Ψs = 1800kPa Ψp = 0kPa Ψs = 1000kPa Ψ = 1000kPa Water relations in the cells are given by the following equation: Ψ cell = Ψs + Ψp

7 (i) alculate the water potential, Ψ, of cell X. Show your working. [2] (ii) State the name of the condition shown by cell Y and explain how this condition could have arisen. [3] (c) (i) ell X has the higher pressure potential Ψp. Explain how this pressure potential is built up in cell X. [3] W10 1071 01 7 (ii) Suggest the effect on seedlings if all of their cells were in the condition as shown in cell Y. [1] (Total 12 marks) Turn over.

8 6. eteropolysaccharides consist of long chains of monosaccharides. Each monosaccharide is attached to a non-carbohydrate part. Bacterial cell walls are made from a heteropolysaccharide consisting of two different monosaccharides abbreviated to NAG and NAM. The linear polymer is made up of alternating NAG and NAM molecules, linked by glycosidic bonds. These chains are arranged in the same way as cellulose of plant cell walls. The glycosidic bonds can be broken by the enzyme lysozyme. 3 2 N 2 4 5 3 2 1 4 3 5 2 1 N 2 N 3 3 3 3 NAM NAG NAM (a) (i) Draw a circle around the part of one of the monosaccharide units that is noncarbohydrate. [1] (ii) n the diagram, draw an arrow labelled B to show a bond which could be broken by the enzyme lysozyme. [1] (iii) Name the type of reaction involved in the breaking of the bond. [1] (iv) Explain what is meant by the phrase arranged in the same way as the chains in cellulose. [3]

9 (b) The diagram shows a molecule of the enzyme lysozyme. 20 Asp Tyr Tyr Leu Ser Leu e Lys Met 10 2 N Leu Glu 1 Lys Val Val Ser 90 Thr lle Glu Val Asp 120 Trp lle ys ys Pne Lys ys S S Be Lys S S AspSer Ser Leu Leu 129 Leu S S Trp Val ys 30 Thr Lys ys 100 Ser Asp Asp Val Ser Pro 70 Leu Thr ys lle Pro 80 ys Ser Asp ys Trp Trp Ser 60 S S Asp Trp 110 Val Trp Met lle Lys Pho Glu Thr Thr Asp Sar Pho Thr 40 Glu Ser 50 lle Leu Gln Thr Asp Tyr (i) State the highest level of protein structure shown in the diagram. [1] (ii) Explain the importance of the S S linkages to the functioning of the enzyme. [3] Turn over.

10 (c) atalase is an enzyme which breaks down hydrogen peroxide into water and oxygen. ydrogen peroxide is a highly toxic waste product of metabolism. An investigation was carried out to determine the relative amounts of catalase in samples of potato, liver and apple. The samples were ground to a pulp and added to hydrogen peroxide in measuring cylinders. The table shows the height of the resulting bubbles in the cylinders. Sample Potato Liver Apple eight of bubbles / cm 3 4 9 1 (i) State two variables that should be controlled during this investigation. [2]...... (ii) From the table, liver contains the most catalase. Suggest an explanation for this result. [2] (Total 14 marks)

11 7. Answer one of the following questions. Any diagrams included in your answer must be fully annotated. Either, (a) The cell (plasma) membrane consists of a number of parts. Describe the structure of the cell membrane and the functions of these parts. [10] r (b) Describe the structure and functions of lipids in plants and animals. [10]........................................................................ Turn over.

12

13 (Total 10 marks)