Name 10 Molecular Biology of the Gene Test Date Study Guide You must know: The structure of DNA. The major steps to replication.

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Name 10 Molecular Biology of the Gene Test Date Study Guide You must know: The structure of DNA. The major steps to replication. The difference between replication, transcription, and translation. How DNA is packaged into a chromosome. The key terms gene expression, transcription, and translation. How to explain the process of transcription. How eukaryotic cells modify RNA after transcription. The steps to translation. How point mutations can change the amino acid sequence of a protein. 1

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1. Review the discovery that DNA is the genetic material and the structures of DNA and RNA. Then match each phrase on the right with the correct term(s) on the left. Note that some answers are used more than once, and some questions have multiple answers. A. Adenine (A) 1 The basic chemical unit of a nucleic acid B. Base 2 The "transforming factor" that alters pneumonia bacteria C. Cytosine (C) 3 The two kinds of nucleic acids D. DNA 4 The three parts of every nucleotide E. E. coli 5 A pair of these forms a "rung" in the DNA ladder F. Double helix 6 Used to "label" DNA and protein in experiments G. Guanine (G) 7 The component of a bacteriophage that enters the host cell H. Hydrogen bond 8 Two alternating parts that form the nucleic acid "backbone" I. Radioactive isotope 9 The four bases in DNA J. Covalent bond 10 The DNA base complementary to T K. Bacteriophage 11 A virus that attacks bacteria L. Protein 12 The substance a phage leaves outside its host cell M. Nucleic acid 13 Ribose in RNA and deoxyribose in DNA N. Nucleotide 14 Watson and Crick deduced the structure of this molecule O. Centrifuge 15 The four bases in RNA P. Phosphate 16 The DNA base complementary to G Q. Polynucleotide 17 A bacterium attacked by T2 and T4 phages R. RNA 18 The sequence of these encodes DNA information S. Sugar 19 Eukaryotic chromosomes consist of this and DNA T. Thymine (T) 20 The overall shape of a DNA molecule U. Uracil (U) 21 Links adjacent nucleotides in a polynucleotide chain 22 23 24 25 Machine used to separate particles of different weights Links a complementary pair of bases together A polymer of nucleotides RNA base that is not in DNA 3

2. Review the structure of DNA by labeling these diagrams. Include nucleotide, polynucleotide, sugar (deoxyribose), phosphate group, sugar-phosphate backbone, pyrimidine bases, purine bases, thymine (T), adenine (A), guanine (G), cytosine (C), hydrogen bond, complementary base pair, and double helix. 3. Reproduction and inheritance involve copying DNA instructions, so that they can be passed to the next generation. This process is carried out by DNA polymerases, enzymes which use each strand of the DNA helix as a template on which to build a complementary strand. Review DNA replication by completing the simplified diagrams below. The first diagram shows the parent DNA molecule; label the nucleotides in the right-hand strand. Complete and label the second diagram, so that it shows the parent strands separating and being used as templates. Label the third diagram, so that it shows two completed daughter molecules of DNA. Color the original DNA strands blue and the new strands red. 4

4. In this diagram showing the replication of DNA, label the following items: leading and lagging strands, Okazaki fragment, DNA polymerase, DNA ligase, helicase, primase, single-strand binding proteins, RNA primer, replication fork, and 5' and 3' ends of parental DNA. 5. Review the processes of transcription and translation by filling in the blanks below. The first step in making a protein is transcription of a gene. This occurs in the 1 of a eukaryotic cell. An enzyme called 2 carries out the process of transcribing RNA from the DNA. It starts at a specific nucleotide sequence called a 3, next to the gene. RNA polymerase attaches, and the two DNA strands separate. RNA polymerase moves along one strand, and as it does, RNA 4 take their places one at a time along the DNA template. They hydrogen bond with complementary bases, following the same pairing rules as in DNA - C with G, and U (replacing T in RNA) with A. As the RNA molecule elongates, it peels away from the DNA. Finally, the enzyme reaches the 5, a base sequence that signals the end of the gene, and the polymerase molecule lets go of the gene and the RNA molecule. In a prokaryote, the RNA transcribed from a gene, called 6 (mrna), can be used immediately in polypeptide synthesis. In a eukaryotic cell, mrna is first processed and then leaves the nucleus and enters the 7 where translation takes place. Translation of the "words" of the mrna message into the 8 sequence of a protein requires an interpreter - 9 (trna) - which links the appropriate 10 with each 11 in the mrna message. A trna molecule is a folded strand of RNA. At one end, a special 12 attaches a specific amino acid. The other end of the trna molecule bears three bases called the 13, which is complementary to a particular mrna codon. During the translation process, the trna matches its amino acid with an mrna codon. 14 are the "factories" where the information in mrna is translated and polypeptide chains are constructed. A ribosome consists of protein and 15 (rrna). Each ribosome has a groove that serves as a binding site for mrna. There are three binding sites for trna: The P site holds the trna carrying the growing 16, the A site holds a trna bearing the next amino acid, and E site is where the trna exits the ribosome. Translation begins with initiation. An mrna and a special 17 trna bind to the ribosome and a specific mrna codon, the 18 where translation begins. The initiator trna generally carries the amino acid methionine (Met). Its anticodon UAC binds to the start codon, 19. The initiator trna fits into the P site on the ribosome. 5

The next step in 20 synthesis is elongation - adding amino acids to the growing chain. The anticodon of an incoming trna, carrying its amino acid, pairs with the mrna codon at the open A site. With help from the ribosome, the polypeptide separates from its trna and forms a peptide bond with the 21 attached to the trna in the A site. Then the "empty" trna in the P site leaves the ribosome, and the trna in the A site, with the polypeptide chain, is shifted to the P site. The mrna and trna move as a unit, allowing the next codon to enter the A site. Another trna, with a complementary anticodon, brings its amino acid to the A site. Its amino acid is added to the chain, the trna leaves, and the complex shifts again. In this way, 22 are added to the chain, one at a time. Finally, a 23 reaches the A site of the 24, terminating the polypeptide. A stop codon causes the polypeptide to separate from the last trna and the 24. The polypeptide folds up, and it may join with other polypeptides to form a larger 25 molecule. 6. Use the genetic code chart to translate the following mrnas into amino acid sequences and answer the questions. mrna nucleotide sequence: (mrna 1) 1. Amino acid sequence: Mutation in mrna: (mrna 2) 2. Amino acid sequence: 3. Number of bases changed in mrna: 4. Type of mutation: 5. Number of amino acids changed: Mutation in mrna: (mrna 3; compare to 1) 6. Amino acid sequence: 7. Number of bases changed in mrna (look carefully!): 8. Type of mutation: 9. Number of amino acids changed (compared to mrna 1): 10. Which mutation had the greatest effect and why? 6

7. Label the diagram below to review the processes of transcription and translation. 7

8. To review the structures and life cycles of viruses, match each phrase on the right with a term from the left. Some answers are used more than once. A. RNA viruses 1 Consists of nucleic acid packaged in protein B. Prophage 2 Leads quickly to breaking open of host cell C. AIDS 3 Phage DNA inserted into bacterial chromosome D. Glycoprotein spikes 4 Responsible for toxins of diphtheria, botulism E. Virus 5 A pair of these forms a "rung" in the DNA ladder F. DNA 6 Rod-shaped plant virus G. Lytic cycle 7 This or DNA may be virus genetic material H. Vaccine 8 Cause of flu, colds, polio, mumps, AIDS I. Nucleus 9 Helps flu or mumps virus enter and leave host cell J. Membranous envelope 10 Used by mumps virus or HIV to attach to host receptors K. Bacteriophage 11 Mumps virus reproduces here L. Provirus 12 Mumps virus makes this and protein from RNA template M. HIV 13 Mumps virus gets envelope from this part of host cell N. Reverse transcriptase 14 Herpesvirus reproduces here O. Lysogenic cycle 15 Genetic material of herpesvirus P. Retrovirus 16 DNA of herpesvirus inserted into host cell DNA Q. White blood cell 17 Can be used to prevent a viral disease R. Prophage genes 18 Virus that causes AIDS S. Tobacco mosaic 19 Genetic material of HIV T. Plasma membrane 20 RNA virus that reproduces by means of DNA U. RNA 21 Enzyme that can make DNA from RNA template V. Cytoplasm 22 Form in which HIV "hides" in host cell W. Hantavirus 23 Acquired immune deficiency syndrome X. Ebola virus 24 Kind of cell infected by HIV 25 26 27 Causes an African sickness Viruses like T2 and T4 that infect bacteria An RNA virus carried by rodents 8